Answer:
6 ; 9 ; 11 ; 12.5; 14
B.) 3.5
Step-by-step explanation:
Given the data:
6 9 9 10 11 11 12 13 14
a.) The low = 6 (lowest value in the dataset)
b.) Q1 = Lower quartile
Q1 = 1/4(n + 1)th term
n = sample size = 9
Q1 = 1/4(9 + 1) ; 1/4(10) = 2.5th term
Q1 = (2nd + 3rd term) / 2 = (9 + 9) / 2 = 9
Median Q2:
Q2 = 1/2(9 + 1) ; 1/2(10) = 5th term = 11
Upper Quartile Q3:
Q3 = 3/4(9 + 1) ; 3/4(10) = 7.5th term
Q3 = (7th + 8th term) / 2 = (12 + 13) / 2 = 12.5
Interquartile range (Q3 - Q1)
(12.5 - 9) = 3.5
The high = 14 (highest value in the dataset)