Answer:
Option C (4096π in²)
Step-by-step explanation:
Area of the circle = 256π in²
We know that [tex]Area=\pi r^{2}[/tex] , where r = radius of the circle
So,
[tex]256\pi = \pi r^{2}[/tex]
Cancelling π from both the sides,
[tex]=> r^{2} = 256[/tex]
[tex]=> r = \sqrt{256} = 16[/tex]
The radius of the circle = 16 in.
When the radius is multiplied with 4 , new radius = 16×4 = 64 in.
New Area = [tex]\pi (64)^{2} =4096\pi \: in^{2}[/tex]
