Answer:
Change in velocity = 4 m/s and acceleration = 0.5 m/s²
Explanation:
Given that,
Initial velocity, u = 3 m/s
Final velocity, v = 7 m/s
Time, t = 8 seconds
(a) The change in velocity of a cyclist.
[tex]\Delta v=v-u\\\\=7\ m/s-3\ m/s\\\\=4\ m/s[/tex]
(b) Acceleration,
[tex]a=\dfrac{\Delta v}{t}\\\\a=\dfrac{4\ m/s}{8\ s}\\\\a=0.5\ m/s^2[/tex]
So, the change in velocity is 4 m/s and acceleration is 0.5 m/s².
