Answer:
position 1 5 8 12 19 25
term -8 8 20 36 64 88
Step-by-step explanation:
(n - 1) is position ( n ∈ N)
d is the distance between the numbers in the sequence
a1 is the first number in the sequence
we have the fuction: a(n) = a1 + (n - 1)d
see in the table, with position = 1, term = -8 => a1 + d = -8
position = 25, term = 88 => a1 + 25d = 88
=> we have: a1 + d = -8
a1 + 25d = 88
=> a1 = -12
d = 4
=> a(n) = -12 + 4(n - 1)
=> term = 8, position = (8 + 12)/4 = 5
position = 8, term = -12 + 4.8 = 20
term = 36, position = (36 + 12)/4 = 12
position = 19, term = -12 + 4.19 = 64
Answer:
The required table is:
Position 1 5 8 12 19 25
Term -8 8 20 36 64 88
Step-by-step explanation:
The general formula for arithmetic sequence is:
[tex]a_n=a_1+(n-1)d[/tex]
where n is the nth term, a₁ is the first term and d is the difference.
Looking at the table, we know that
a₁ = -8 and
a₂₅ = 88
We can find the common difference d:
[tex]a_n=a_1+(n-1)d\\n=25, a_1=-8, a_{25}=88\\a_{25}=a_1+(25-1)d\\88=-8+24(d)\\88+8=24\:d\\96=24\:d\\d=\frac{96}{24}\\d=4[/tex]
So, we have d = 4
Now we can fill the remaining table.
We have to find position n, when term (a_n) is 8
[tex]a_n=a_1+(n-1)d\\8=-8+(n-1)4\\8=-8+4n-4\\8=-12+4n\\8+12=4n\\20=4n\\n=\frac{20}{4}\\n=5[/tex]
So, when term is 8, position is 5
We have to find term a_n when position n is 8
[tex]a_n=a_1+(n-1)d\\a_8=-8+(8-1)4\\a_8=-8+7(4)\\a_8=-8+28\\a_8=20[/tex]
So, when position is 8 term is 20
We have to find position n, when term (a_n) is 36
[tex]a_n=a_1+(n-1)d\\36=-8+(n-1)4\\8=-8+4n-4\\8=-12+4n\\36+12=4n\\48=4n\\n=\frac{48}{4}\\n=12[/tex]
So, when term is 36, position is 12
We have to find term a_n when position n is 19
[tex]a_n=a_1+(n-1)d\\a_{19}=-8+(19-1)4\\a_{19}=-8+18(4)\\a_{19}=-8+72\\a_{19}=64[/tex]
when position is 19 term is 64
So, the required table is:
Position 1 5 8 12 19 25
Term -8 8 20 36 64 88
