Answer:
Length of Mr. Roger's field = 5 miles
Step-by-step explanation:
Given that:
Area of Mr. Roger's field = [tex]3\frac{1}{3}=\frac{10}{3}[/tex] square miles
Width of Mr. Roger's field = [tex]\frac{2}{3}[/tex] of a mile
Let,
l be the length of Mr. Roger's field
Area of field = Length * Width
[tex]\frac{10}{3}=\frac{2}{3}l[/tex]
Multiplying both sides by 3/2
[tex]\frac{3}{2}*\frac{10}{3}=\frac{2}{3}l*\frac{3}{2}\\5 = l\\l = 5[/tex]
Hence,
Length of Mr. Roger's field = 5 miles
