Answer:
0.433 s
Explanation:
Let's break the projectile motion into its horizontal and vertical components:
Horizontal component (x):
Vertical component (y):
We want to find the time required for the hurdler to travel a distance of 0.635 m. In order words, his displacement should be 0.635 m in the x-direction.
Since we don't have the final velocity, we can use this constant acceleration equation:
We have three known variables and want to solve for t. Using this equation in the x-direction, we have:
- Δx = 0.635 m
- v₀ = 3.22 * cos(62.9)
- a = 0 m/s²
- t = ?
Substitute these values into the equation.
- 0.635 = [3.22 * cos(62.9)] t + 1/2(0) t²
Simplify the equation.
- 0.635 = 3.22 * cos(62.9) t
Divide both sides by the horizontal component of the initial velocity.
Since we start with 3 sig figs, we will round this value to 0.433. The time it takes to clear the hurdle is 0.433 seconds.
