Answer:
C. [tex] \frac{h}{j} = \frac{k}{i} [/tex]
Step-by-step explanation:
Given that [tex] \overline{TU} [/tex] is parallel to [tex] \overline{QR} [/tex], therefore:
[tex] \frac{ST}{TQ} = \frac{SU}{UR} [/tex]
ST = h
TQ = j
SU = k
UR = i
Therefore substituting these into the equation, we have:
[tex] \frac{h}{j} = \frac{k}{i} [/tex]