Answer:
x = ~0.1289 m/s^2
Explanation:
We can use one of the kinematic formulas. We see that the equation doesn’t contain the final velocity, so we use the kinematic equation d = v_0t + (1/2)at^2.
Since the train started from rest, the initial velocity, v_0, is 0. Thus, the equation becomes:
d = (1/2)at^2
Note that 5 minutes is 300 seconds and 5.8 km is 5800 m. Substituting the values we are given, we get:
5800 m = (1/2)(x m/s^2)(300 s)^2 = (45000 s^2)(x m/s^2)
Dividing by 45,000 on both sides, we get:
x = ~0.1289 m/s^2
I hope this helps! :)
