Answer:
2.66secs
Explanation:
To get the time it will take to reach the ground, we will use the equation of motion;
S = ut + 1/2at²
S is the distance
u is the initial velocity
g is the acceleration due to gravity
Given
S = 30m
u = 0m/s
Let's get the acceleration
According to newton's second law;
[tex]\F_x = ma_x\\F_m - F_f = ma_x\\mgsin \theta - 0 = ma_x\\gsin\theta = a_x\\a_x = 9.8sin 60\\a_x = 9.8(0.8660)\\a_x = 8.49m/s^2[/tex]
Get the required time:
Recall that: S = ut + 1/2at²
Substitute the given parameters and find t
30 = 0(t) + 1/2(8.49)t²
30 = 4.24t²
t² = 30/4.24
t² = 7.08
t = √7.08
t = 2.66secs
Hence it take the box 2.66seconds to reach the ground
