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Describe how the graph of y= x2 can be transformed to the graph of the given equation.
y = (x - 12)^2 + 3 (5 points)

a) Shift the graph of y = x^2 up 12 units and then right 3 units.
b) Shift the graph of y = x^2 left 12 units and then down 3 units.
c) Shift the graph of y = x^2 left 12 units and then up 3 units.
d) Shift the graph of y = x^2 right 12 units and then up 3 units.

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Answer:

Non of the above.

But graph y=x² must be shifted upward 147 units, or i√3+12 units to the right.

NOTE:. i√3+12 is the same as (√-3)+12

or if the equation that is shifted must be y=(x-12)²

Step-by-step explanation:

[tex]y = {(x - 12)}^{2} + 3 \\ intercepts \\ when \: y = 0 \: \: \: x = i \sqrt{3} + 12(complex \: number) \\ when \: x = 0 \: \: \: y = 147[/tex]

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