Answer:
[tex]F=3.93\times 10^{-7}\ N[/tex]
Explanation:
Mass of student 1, m₁ = 79 kg
Mass of student 2, m₂ = 93.5 kg
The students are 1.12 m apart, d = 1.12 m
We need to find the force of the gravitational attraction between them. The force of gravitational force is given by :
[tex]F=G\dfrac{m_1m_2}{r^2}\\\\F=6.67\times 10^{-11}\times \dfrac{79\times 93.5}{(1.12)^2}\\\\=3.93\times 10^{-7}\ N[/tex]
So, the force of gravitational attraction between them is [tex]3.93\times 10^{-7}\ N[/tex]. Hence, the correct option is (B).
