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Which equation represents a circle that contains the point (–5, –3) and has a center at (–2, 1)?

Distance formula: StartRoot (x 2 minus x 1) squared + (y 2 minus y 1) squared EndRoot

(x – 1)2 + (y + 2)2 = 25
(x + 2)2 + (y – 1)2 = 5
(x + 2)2 + (y – 1)2 = 25
(x – 1)2 + (y + 2)2 = 5

Respuesta :

Answer:

(x + 2)² + (y - 1)² = 25

Step-by-step explanation:

radius: r² = (1 - (-3))² + (-2 - (-5))² = 16 + 9 = 25

r = 5

Circle: (x - h)² + (y - k)² = r²

center: (-2 , 1)      h = -2       k = 1

(x + 2)² + (y - 1)² = 25

abidemiokin

The equation represents a circle that contains the point (–5, –3) and has a center at (–2, 1) is (x+2)^2 + (x-1)^2 = 25

Equation of a circle

The standard equation of a circle is expressed as:

(x-a)^2+(y-b)^2 = r^2

where:

(a, b) is the centre

r is the radius

Given the following parameters

(a, b) = (-2, 1)

r² = (1 - (-3))² + (-2 - (-5))² = 16 + 9 = 25

Substitute into the formula to have:

(x-(-2))^2 + (x-1)^2 = 25

(x+2)^2 + (x-1)^2 = 25

Hence the equation represents a circle that contains the point (–5, –3) and has a center at (–2, 1) is (x+2)^2 + (x-1)^2 = 25

Learn more om equation of a circle here: https://brainly.com/question/1506955

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