Answer:
[tex]E = -6 \ N/C[/tex]
Generally given that the electric field is negative it mean that its direction is opposite to that of the force
Explanation:
From the question we are told that
The charge on the small object is [tex]Q = -4.00 \ nC = -4.00 *10^{-9} \ C[/tex]
The force is [tex]F = 24 \ nN = 24 *10^{-9} \ N[/tex]
Generally the magnitude of the electric field is mathematically represented as
[tex]E = \frac{F}{Q}[/tex]
=> [tex]E = \frac{ 24 *10^{-9}} {-4 *10^{-9 }}[/tex]
=> [tex]E = -6 \ N/C[/tex]
Generally given that the electric field is negative it mean that its direction is opposite to that of the force
