Answer:
[tex]KE_{new}=186300 J[/tex]
Explanation:
Given:
[tex]KE=2300J[/tex] [tex]n=9[/tex]
[tex]v_{new}=n*v_{old}[/tex]
[tex]\frac{KE_{new}}{KE_{old}}=\frac{v^2_{new}}{v^2_{old}}=\frac{(n*v_{old})^2}{v^2_{old}}=n^2[/tex]
[tex]KE_{new}=n^2KE_{old}[/tex]
[tex]KE_{new}=(9)^2(2300)[/tex]
[tex]KE_{new}=186300 J[/tex]
Scientific notation
[tex]KE_{new}= 1.863*10^5 J[/tex]
Hope it helps
