Answer:
0.0500L of 3.00M HCl are needed to react completely
Explanation:
Hydrochloric acid HCl reacts with sodium carbonate, Na2CO3, as follows:
2HCl + Na₂CO₃ → 2NaCl + H₂O + CO₂
Where 2 moles of HCl reacts per mole of Na₂CO₃
To find the volume of 3.00M HCl needed to react completely we need first to calculate the moles of Na₂CO₃ added and, with this chemical equation we can solve for moles of HCl as follows:
Moles Na₂CO₃:
0.750L * (0.100moles Na₂CO₃ / L) = 0.0750moles
Moles HCl:
0.0750moles Na₂CO₃ * (2 moles HCl / 1 mole of Na₂CO₃) = 0.150 moles of HCl
Volume of 3.00M HCl:
0.150 moles of HCl * (1L / 3.00moles) =
0.0500L of 3.00M HCl are needed to react completely
