Answer:
a) 19536 joules of work are done.
b) The work is done by the engine on the structure of the cart.
c) There are three options: (i) Keeping the engine and changing the travelled distance, (ii) Changing the engine and keeping the travelled distance, (iii) Changing the engine and the travelled distance.
d) 24442 joules of work are done.
e) We may change for a bigger engine if it allows a greater acceleration and higher peak speed.
f) The bigger engine uses more gas to go 22 meters.
g) An empty semi truck uses more gas than a car since the first has much more mass than a car and is designed for moves big loads and for being fast.
Explanation:
a) If force applied in the cart is uniform, that is, constant in magnitude and direction and is parallel to distance travelled by the car, the work done on the cart is defined by the following equation:
[tex]W = F\cdot \Delta s[/tex] (1)
Where:
[tex]F[/tex] - Force applied by the cart, measured in newtons.
[tex]\Delta s[/tex] - Distance travelled by the car, measured in meters.
[tex]W[/tex] - Work done on the cart, measured in joules.
If we know that [tex]F = 888\,N[/tex] and [tex]\Delta s = 22\,m[/tex], then the work done on the cart is:
[tex]W =(888\,N)\cdot (22\,m)[/tex]
[tex]W = 19536\,J[/tex]
19536 joules of work are done.
b) The work is done by the engine on the structure of the cart.
c) There are three options: (i) Keeping the engine and changing the travelled distance, (ii) Changing the engine and keeping the travelled distance, (iii) Changing the engine and the travelled distance.
d) If we know that [tex]F = 1111\,N[/tex] and [tex]\Delta s = 22\,m[/tex] , then the work on the cart is:
[tex]W = (1111\,N)\cdot (22\,m)[/tex]
[tex]W = 24442\,N[/tex]
24442 joules of work are done.
e) We may change for a bigger engine if it allows a greater acceleration and higher peak speed.
f) The gas consumption is directly proportional to the square of velocity and mass of the cart and, hence, to the work done on the cart. In consequence, we conclude that the bigger engine uses more gas to go 22 meters.
g) An empty semi truck uses more gas than a car since the first has much more mass than a car and is designed for moves big loads and for being fast.
a. The amount of work done by the go cart engine is 19,536 Nm.
b. Work is being done by the go cart engine i.e the engine installed on the go cart.
c. The amount of work will increase if the driver wants to go further because work done is directly proportional to the distance covered. No, you don't need a bigger engine to go further.
d. The amount of work done when a bigger engine is used is 24,442 Nm.
e. The reason why a bigger engine is used is, so that the engine can easily do more work in the same amount of distance.
f. Since we know that work requires a change in energy, the bigger engine would use more gas to go 22 meters.
g. An empty semi truck uses much more gas than a car because it has more weight (mass) and as such requires more energy, in accordance with the law of inertia.
Given the following data:
a. To determine the amount of work done by the go cart engine:
Mathematically, the work done by an object is given by the formula;
[tex]Work\;done = Force \times distance[/tex]
Substituting the given parameters into the formula, we have;
[tex]Work\;done = 888 \times 22[/tex]
Work done = 19,536 Nm.
b. Work is being done by the go cart engine i.e the engine installed on the go cart.
c. The amount of work will increase if the driver wants to go further because work done is directly proportional to the distance covered. No, you don't need a bigger engine to go further.
d. To determine the amount of work done when a bigger engine is used:
[tex]Work\;done = Force \times distance[/tex]
[tex]Work\;done = 1111 \times 22[/tex]
Work done = 24,442 Nm.
e. The reason why a bigger engine is used is, so that the engine can easily do more work in the same amount of distance.
f. Since we know that work requires a change in energy, the bigger engine would use more gas to go 22 meters.
g. An empty semi truck uses much more gas than a car because it has more weight (mass) and as such requires more energy, in accordance with the law of inertia.
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