Respuesta :
Answer:
Orbital geometry is Tetrahedral
Molecular geometry is Bent/V shape
Explanation:
Using the VSEPR theory which states that
- The shape of a molecule depends upon the number of valence shell electron pairs (bonded or nonbonded) around the central atom.
- Pairs of electrons in the valence shell repel one another since their electron clouds are negatively charged.
- These pairs of electrons tend to occupy such positions in space that minimize repulsion and thus maximize distance between them.
- The valence shell is taken as a sphere with the electron pairs localizing on the spherical surface at maximum distance from one another.
- A multiple bond is treated as if it is a single electron pair and the two or three electron pairs of a multiple bond are treated as a single super pair.
- Where two or more resonance structures can represent a molecule, the VSEPR model is applicable to any such structure
so we have Y as the central atom and it has 2X substituents on its either sides with two lone pairs on Y. This is a case of Y which has
2 bonds with X on either sides
2 lone pairs on Y
The orbital geometry will be Tetrahedral but its Molecular geometry will be Bent/V shaped
The formula of the compound will be YX2
Water with chemical Formula of H2O bears the same features.
The shape of the given molecule according to the VSEPR theory has been Bent/V shape.
VSEPR theory has been the Valence Shell Electron Pair Repulsion theory. It helps in the determination of the molecular and geometrical shape based on the presence of the atoms attached.
The given molecule has the presence of 2 single-bonded X atoms.
The atoms repel each other, while the presence of loan pairs results in the force for the molecule to occupy the tetrahedral orbital geometry. The repulsion from the loan pair to the X atoms acquires the Bent V shape as molecular geometry.
For more information about the VSEPR theory, refer to the link:
https://brainly.com/question/14225705
