Answer:
292.7 g
Explanation:
Note: the reaction is missing but I looked it up on the web and found it.
Step 1: Write the balanced equation
CuSO₄(aq) + 2 NaOH(aq) → Cu(OH)₂(s) + Na₂SO₄(aq)
Step 2: Calculate the moles corresponding to 240.0 g of NaOH
The molar mass of NaOH is 40.00 g/mol.
240.0 g × 1 mol/40.00 g = 6.000 mol
Step 3: Calculate the moles of Cu(OH)₂ formed from 6.000 moles of NaOH
The molar ratio of NaOH to Cu(OH)₂ is 2:1. The moles of Cu(OH)₂ formed are 1/2 × 6.000 mol = 3.000 mol.
Step 4: Calculate the mass corresponding to 3.000 moles of Cu(OH)₂
The molar mass of Cu(OH)₂ is 97.56 g/mol.
3.000 mol × 97.56 g/mol = 292.7 g
