Respuesta :
Answer:
Hii!!
Volume Of Sphere =[tex] \frac{4}{3} * π * r^3. [/tex]
Let r be 1cm, 3 cm, 6 cm.
So,
Volume of sphere 1 = [tex] \frac{4}{3} * 3.14 * 1^3. [/tex]
Volume of sphere 1 = 4.19 cm^3
Volume of sphere 2 = [tex] \frac{4}{3} * 3.14 * 3^3. [/tex]
Volume of sphere 2 = 113.04cm^3
Volume of sphere 3 = [tex] \frac{4}{3} * 3.14 * 6^3. [/tex]
Volume of sphere 3 = 904.32 cm^3
Volume of cylinders = [tex] π * r^2 * h. [/tex]
Let r be 1cm, 3 cm, 6 cm and h be 2cm, 6cm and 12cm respectively.
So,
Volume of cylinder 1 = [tex] π * 1^2 * 2. [/tex]
Volume of cylinder 1 = 6.28 cm^3
Volume of cylinder 1 = [tex] π * 3^2 * 6. [/tex]
Volume of cylinder 1 = 169.56 cm^3
Volume of cylinder 1 = [tex] π * 6^2 * 12. [/tex]
Volume of cylinder 1 = 1356.48 cm^3
HOPE IT HELPS!!!
BRAINLIEST PLS!!!!
We can write the volume of spheres with three different radii as given below
[tex]\rm Let\; R_1 , R_2, R_3 \; be \; the \; three\; radii\; of \; sphere \; respectively \\\\\rm Volume \; of \; first \; sphere = (4/3) \pi \ R_1^3 \\\\\rm Volume \; of \; second \; sphere = (4/3) \pi \ R_2^3 \\\\Volume \; of \; third \; sphere = (4/3) \pi \ R_3^3[/tex]
Also we can write the the volume of the cylinders as follows
[tex]\rm Volume \; of \; first \; cylinder = \pi R_1 ^2H_1 = \pi R_1^2 (2R_1) = 2 \pi R_1^3[/tex]
[tex]\rm Volume \; of \; second\; cylinder = \pi R_2^2H_2 = \pi R_2^2 (2R_2) = 2 \pi R_2^3[/tex]
[tex]\rm Volume \; of \; third \; cylinder = \pi R_3 ^2H_3 = \pi R_3^2 (2R_3) = 2 \pi R_3^3[/tex]
Volume of a sphere with radius R is given by equation
[tex]\rm Volume \; of \; the \; sphere \; of\; radius\; R = \bold{4/3 \pi R^3 }[/tex]
[tex]\rm Let\; R_1 , R_2, R_3 \; be \; the \; three\; radii\; of \; sphere \; respectively \\\\\rm Volume \; of \; first \; sphere = (4/3) \pi \ R_1^3 ........(1) \\\\\rm Volume \; of \; second \; sphere = (4/3) \pi \ R_2^3 .........(2) \\\\Volume \; of \; third \; sphere = (4/3) \pi \ R_3^3..........(3)[/tex]
Equation (1) (2) and (3) represent the volumes of three different spheres
Given that the heights of the cylinders are equal to the diameter of the spheres
so from this given condition we can write the following relations
[tex]\rm Height\; of \; first \; sphere = H_1 = 2R_1 \\\\ Height\; of \; second \; sphere = H_2 = 2R_2 \\\\Height\; of \; third \; sphere = H_3 = 2R_3 \\\\[/tex]
The volume of the cylinder is given by equation (4)
[tex]\rm Volume \; of \; the\; cylinder = \pi R^2 H........(4) \\\\Where R = Radius \; of \; the \; cylinder \\\\H \; is \; the \; Height \; of \; the\; cylinder\\[/tex]
From the given conditions of heights of cylinders and radius of the sphere.
We can write the the volume of the cylinders as follows
[tex]\rm Volume \; of \; first \; cylinder = \pi R_1 ^2H_1 = \pi R_1^2 (2R_1) = 2 \pi R_1^3[/tex]
[tex]\rm Volume \; of \; second\; cylinder = \pi R_2^2H_2 = \pi R_2^2 (2R_2) = 2 \pi R_2^3[/tex]
[tex]\rm Volume \; of \; third \; cylinder = \pi R_3 ^2H_3 = \pi R_3^2 (2R_3) = 2 \pi R_3^3[/tex]
For more information please refer to the link given below
https://brainly.com/question/12748872