Answer:
The equation of the line in slope-intercept form is;
y = 10 - 5/6·x
Step-by-step explanation:
The given equation of the line to which the required line is perpendicular is presented as follows;
y = 6/5·x + 9
A point on the desired line = (12, 0)
The relationship of the slope, m₁ of a line, perpendicular to the another line of slope m₂, is given as follows;
m₁ = -1/m₂
Therefore;
The slope of the desired line = -1/(The slope of the given line)
The slope of the desired line = -1/(6/5) = -5/6
The equation of the desired line in point and slope form is given as follows;
y - 0 = -5/6 × (x - 12)
Therefore, the equation of the line in slope-intercept form is;
y = -5/6·x + 10 = 10 - 5/6·x.
