Answer:
the fox moves mn times as fast as the squirrel
Step-by-step explanation:
the easiest way to do problems like this is by using hypothetical values that make sense (it's best to avoid 0, 1, and 2)
we'll say that n = 3 and m = 4
so if the squirrel moves at s pace, then the rabbit moves at ns, or 3s.
if the fox moves at m (4) times the rabbit's pace (3s), then it moves at 4(3s)
then just switch out the numbers for their variables, giving you m(ns)
remember that s simply represents the squirrel's pace, we cannot replace it with a number in this case, so switch it with the idea/value it represents
and there you go, mn times the squirrel's pace
