Answer:
Step-by-step explanation:
We can find the solution to a system of equations by graphing the equations. Let's do this with the following systems of equations:
\goldD{y=\dfrac{1}{2}x+3}y=
2
1
x+3start color #e07d10, y, equals, start fraction, 1, divided by, 2, end fraction, x, plus, 3, end color #e07d10
\greenE{y=x+1}y=x+1start color #0d923f, y, equals, x, plus, 1, end color #0d923f
First, let's graph the first equation \goldD{y=\dfrac{1}{2}x+3}y=
2
1
x+3start color #e07d10, y, equals, start fraction, 1, divided by, 2, end fraction, x, plus, 3, end color #e07d10. Notice that the equation is already in yyy-intercept form so we can graph it by starting at the yyy-intercept of 333, and then going up 111 and to the right 222 from there.
Next, let's graph the second equation \greenE{y=x+1}y=x+1start color #0d923f, y, equals, x, plus, 1, end color #0d923f as well.
