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Use technology to find the​ P-value for the hypothesis test described below. The claim is that for a smartphone​ carrier's data speeds at​ airports, the mean is μ=11.00 Mbps. The sample size is n=14 and the test statistic is t=1.484. ​P-value=nothing ​(Round to three decimal places as​ needed.)

Respuesta :

Solution :

The null and alternative hypothesis is given by

[tex]$H_0: \mu = 11$[/tex]

[tex]$H_a: \mu \ne 11$[/tex]

Assume that the level of significance, α = 0.05

The t-test statistics is, t = 1.484

Degree of freedom :

df = n - 1

   = 14 - 1

   = 13

The P-value is given by

P-value = 2P (T>|t|)

            = 2P(T>|1.484|)

            = 2P(T>1.484)

            = 2(=T.DIST.RT(1.484,13))

            = 0.05

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