Answer:
normal distribution can be used to model the sample proportions
Step-by-step explanation:
N ( sample size ) = 100
probability of earning high school diploma (p) = 0.87
probability of not earning high school diploma ( q ) = 0.13
hence ;
∈( P ) = p = 0.87
Var ( p ) = [tex]\frac{pq}{n}[/tex] = [tex]\frac{0.86 * 0.13 }{100}[/tex] = 0.001131
therefore ; p ~ N = ( 0.87 , 0.001131 )