Answer:
Therefore, the pressure exerted by the hydrogen gas that was trapped over water is 108.8 kPa
Explanation:
The law of partial pressure by Dalton, in a mixture of gases which do not react chemically together, the total pressure is equal to the sum of the partial pressures of the individual gases.
According to this law, the total pressure exerted by the gases above the displaced water is equal to the sum of the partial pressure of water vapor and the partial pressure of hydrogen gas: Ptotal = pH₂ + pH₂O
Therefore, pH₂ = Ptotal - pH₂O
Vapor pressure of water at 37°C = 3.17 kPa; Ptotal = 102.0 kPa
pH₂ = (102.0 - 3.17) kPa
pH₂ = 98.8 kPa
Therefore, the pressure exerted by the hydrogen gas that was trapped over water is 108.8 kPa
