Answer:
0.02088M of EDTA
Explanation:
The Ca²⁺ is chelated in presence of EDTA in a relation 1:1, when there is no free Ca²⁺ the eriochorme black T change its colour showing endpoint.
Thus, we need to find final concentration of Ca²⁺ solution and, thus, we can find concentration of the EDTA solution:
Molarity Ca²⁺ solution:
0.2191g * (1mol / 40.08g) = 0.005467 moles of Ca²⁺ in 250mL = 0.250L:
0.005467 moles of Ca²⁺ / 0.250L = 0.02187M
Moles of Ca²⁺ added:
0.025L * (0.02187 mol / L) = 5.467x10⁻⁴ moles of Ca²⁺ = Moles of EDTA at endpoint.
Molarity EDTA:
5.467x10⁻⁴ moles EDTA / 0.02618L = 0.02088M of EDTA