Answer:
[tex]\huge\mathtt{{\colorbox{silver}{ANSWER~~~↴}}}[/tex]
ꜰɪʀꜱᴛ ᴡᴇ ᴡʀɪᴛᴇ ᴛʜᴇ ɢɪᴠᴇɴ↴
⇒WIDTH = Y cm
⇒LENGTH =( y+2 )cm
⇒PERIMETER = 32cm
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solution ↴
perimeter of rectangle = 2 ( length + width)
[tex]32cm = 2( (y +2) +y )cm \\ \frac{32}{2} cm = 2y + 2cm \\ 16cm = 2y - 2cm \\ 16 cm- 2 cm=2y\\ 14cm = 2y \\ y = \frac{14cm}{2} \\ y = 7cm
[/tex]
☛ so the width of the rectangle is 7cm
so we all done :D
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