Answer:
Step-by-step explanation:
Let the amount of nickels be x
Let the amount of dimes be y
Let the amount of quarters be z
If the total collection amounts to $9.50, then;
x+y+z = 9.50 ..... 1
If there are four times as many quarters as nickels, then;
z = 4x .... 2
Also if there are 3 more dimes than nickels then;
y = x+3 .... 3
Substitute 2 and 3 into 1;
x + x+3 + 4x = 9.50
6x = 9.50 -5
6x = 4.50
x = 4.50/6
x = $0.75
Since y = x +3
y = 0.75 + 3
y = $3.75
Also, z = 4x
z = 0.75(5)
z = $3.0
Hence there are