Answer:
Step-by-step explanation:
sqrt(i^2*16*3) = 4i[tex]\sqrt{3\\}[/tex]
sqrt(i^2*9*7) = 3i[tex]\sqrt{7}[/tex]
sqrt(i^2*36*2) = 6i[tex]\sqrt{2}[/tex]
sqrt(i^2*6*4) = 2i[tex]\sqrt{6}[/tex]
sqrt(i^2*4*3*7) = 2i[tex]\sqrt{21}[/tex]
sqrt(i^2*9*11)= 3i[tex]\sqrt{11}[/tex]