Answer:
0.42 ft
0.92 ft
Step-by-step explanation:
Width of mural on painting = 5 inches
Height of mural on painting = 11 inches
12 inches of the painting represents 1 foot of the mural
1 inch of the painting represenets [tex]\dfrac{1}{12}[/tex] foot of the mural.
[tex]5\ \text{inches}=5\times \dfrac{1}{12}=0.42\ \text{ft}[/tex]
[tex]11\ \text{inches}=11\times\dfrac{1}{12}=0.92\ \text{ft}[/tex]
The width of the mural is 0.42 ft and height of the mural is 0.92 ft.
The height and width of the actual mural into the boxes is 0.92 ft and 0.42 ft.
Since
Arnold painted the picture on a paper that is 5 inches wide and 11 inches tall. Arnold is using a scale in which 12 inch represents 1 foot to paint the mural.
So here the width should be 5 of 1 by 12 should be 0.42 feet
And, the height should be 11 of 1 by 12 should be 0.92 ft.
Hence, The height and width of the actual mural into the boxes is 0.92 ft and 0.42 ft.
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