9514 1404 393
Answer:
a) (-5±√10)/3 ≈ {-2.721, -0.613}
b) (6±√21)/5 ≈ {0.283, 2.117}
Step-by-step explanation:
a) The relevant coefficients are ...
a = 3, b = 10, c = 5
[tex]x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\x=\dfrac{-10\pm\sqrt{10^2-4\cdot3\cdot5}}{2\cdot3}=\dfrac{-10\pm\sqrt{40}}{6}\\\\\boxed{x=\dfrac{-5\pm\sqrt{10}}{3}\approx\{-2.721, -0.613\}}[/tex]
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b) The relevant coefficients are ...
a = 5, b = -12, c = 3
[tex]x=\dfrac{-(-12)\pm\sqrt{(-12)^2-4\cdot5\cdot3}}{2\cdot5}=\dfrac{12\pm\sqrt{84}}{10}\\\\\boxed{x=\dfrac{6\pm\sqrt{21}}{5}\approx\{0.283, 2.117\}}[/tex]
