Given:
Equation of line is
[tex]y=1.2x+3.8[/tex]
To find:
The equation of line that passes through the point (5, 0) and parallel to the given line.
Solution:
Slope intercept form of a line is
[tex]y=mx+b[/tex]
where, m is slope and b is y-intercept.
On comparing the given equation [tex]y=1.2x+3.8[/tex] with the slope intercept form, we get
[tex]m=1.2[/tex]
So, slope of given line is 1.2.
Slope of parallel lines are same. So, slope of required line is 1.2.
The required line passes through (5,0) having slope 1.2. So, the equation of line is
[tex]y-y_1=m(x-x_1)[/tex]
where, m is slope of the line.
[tex]y-0=1.2(x-5)[/tex]
[tex]y=1.2x-1.2(5)[/tex]
[tex]y=1.2x-6[/tex]
Therefore, the correct option is A.
