Respuesta :
Using the inverse binomial distribution, it is found that there is a 0.081 = 8.1% probability that the third caller is the first to correctly answers the question.
The number of callers that correctly answer the question is a binomial variable, however, we want the probability of the third caller being the first to answer the question correctly, hence it is a negative binomial variable.
Inverse binomial:
It is the number of trials until q successes of a binomial variable, with p probability of success.
The probability mass function is:
[tex]P(X = x) = C_{x+q-1,q-1}(1 - p)^xp^q[/tex]
[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]
In this question:
- Number of trials until 1 success, hence [tex]q = 1[/tex].
- 0.1 probability of a success on each trial, hence [tex]p = 0.1[/tex].
The probability that the third caller is the first to correctly answers the question is P(X = 3), hence:
[tex]P(X = x) = C_{x+q-1,q-1}(1 - p)^xp^q[/tex]
[tex]P(X = 3) = C_{3,0}(0.9)^2(0.1)^1 = 0.081[/tex]
0.081 = 8.1% probability that the third caller is the first to correctly answers the question.
To learn more about the inverse binomial distribution, you can take a look at https://brainly.com/question/14581720