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The two insulated beakers shown contain equal amounts of identical liquids. The temperature of Beaker A is 80°C. The temperature of Beaker B is 50°C. A copper rod connects the beakers. The system is then left alone for several hours. What would you expect to find when the system is examined after this time?

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Answer:

After several hours, both beakers are expected to have the same temperature of 65°C

Explanation:

Given that:

The temperature in beaker A = 80°C

The temperature in beaker B = 50°C

The copper rod used to connect allows transference to heat and temperature from beaker A to the beaker B  because it is a good conductor of heat and electricity. After several hours, movement of heat and the temperature have occurred and they have both reached equilibrium.

Therefore, after several hours, both beakers are expected to have the same temperature of 65°C

i.e.

= ((80 + 50)/2) °C

= (130/2)°C

= 65 °C

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