Answer:
we have zero degree of freedom (F = 0) at the first phase region and one degree of freedom (F = 1) at the second phase region
Explanation:
given the diagram;
C = 2 { Ti and Ni}, N = 1 {Pr is constant}, P = 3 { L and B}
For degree of freedom,
Gibbs phase rule is applied for invariant point (ex.A)
P + F = C + N
3 + F = 2 + 1
F = 3 - 3
F = 0
For the second phase region ( ex.B)
C = 2, N = 1, P = 2
P + F = C + N
2 + F = 2 + 1
F = 3 - 2
F = 1
Therefore we have zero degrees of freedom (F = 0) at the first phase region and one degrees of freedom (F = 1) at the second phase region
