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[tex]\boxed{ \large{ \sf{Question: }}}[/tex]
Five years ago,A's age was four times the age of B.Five years hence A's age will be twice of the age of B. Find their present ages.
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Answer:

Let us consider B’s age = X

Then A’s age = 4X

Five years ago

⇒ A’s age = 4X + 5

⇒ B’s age = X + 5

Five years hence

⇒ A’s age = 4X + 5 + 5

⇒ A’s age = 4X + 10

⇒ B’s age = X + 5 + 5

⇒ B’s age = X + 10

From the given question

4X + 10 = 2(X + 10)

4X + 10 = 2X + 20

4X – 2X = 10

2X = 10

X = 5

A’s age = 4X + 5

A’s age = 25 years

B’s age = X + 5

B’s age = 10 years

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