Answer: [tex]\dfrac{10}{91}[/tex]
Step-by-step explanation:
Given : The jar contains 5 Snickers, 2 Butterfingers, 4 Almond Joys and 3 Milky Ways.
Total candies in the jar =[tex]5+2+4+3=14[/tex]
Provability that firsts student select snickers =[tex]\dfrac{5}{14}[/tex]
Now total candies in jar = 14-1=13
Total snickers remained =5-1=4
Probability that the second student also select snickers=[tex]\dfrac{4}{13}[/tex]
Then, the probability that the first student picks a Snickers and then the second student also picks a Snickers :-
[tex]\dfrac{5}{14}\times\dfrac{4}{13}=\dfrac{20}{182}=\dfrac{10}{91}[/tex]
Hence, the required probability = [tex]\dfrac{10}{91}[/tex]
