Hooke's Law. The distance d when a spring is stretched by a hanging object varies directly as the weight w of the object. If the distance is
68 cm when the weight is 2 kg, what is the distance when the weight is 5 kg?
It would just be 2x68, in the sense that the original equation for Hooke's Law is F=kX. In your equation, w is k and X is D. the answer is 136cm for 2kg and 340cm for 5kg. Tell me if this is wrong please.
