A package has a mean mass of 340 g and a standard deviation of 1.5 g. Assuming that the masses are normally distributed, find the percent of packages with a mass below 336.7 g
The z-score for a weight of 336.7g is found as follows; [tex]z=\frac{336.7-340}{1.5}=-2.2[/tex] The cumulative probability for a z-score of -2.2 can be found from a normal distribution table: The cumulative probability for a z-score of -2.2 is 0.0139. Therefore the answer is 1.39%.
