Answer:
The quadrant in which point S lie is:
Quadrant 4.
since, the x-coordinate is positive and y-coordinate is negative
Step-by-step explanation:
We know that if the point C(c,d) lies in between A(a,b) and B(a',b') then the coordinates of the point C is given by:
[tex]c=\dfrac{a+a'}{2}\ ,\ d=\dfrac{b+b'}{2}[/tex]
Here the midpoint of segment TS is the origin i.e. (c,d)=(0,0)
A=T and B=S
Also, Point T is located in Quadrant 2.
i.e. a<0 and b>0
We have:
[tex]0=\dfrac{a+a'}{2}\ ,\ 0=\dfrac{b+b'}{2}\\\\a+a'=0\ ,\ b+b'=0\\\\a'=-a\ ,\ b'=-b[/tex]
Hence, we have:
[tex]a'>0\ ,\ b'<0[/tex]
This means that point S lie in quadrant 4
