Answer:
[tex]B. \: \boxed{66.8}[/tex]
Step-by-step explanation:
[tex]to \: solve \: this \: little \: poblem : we \:apply \: the \: pythagrean \: rule \to \\ \boxed{SOH} \boxed{CAH} \boxed{TOA} \to \\ we \: are \: been \: given : \to \\ the \: \boxed{opp }\: of \: the \: required \: angle \: = 35. \\ the \: \boxed{adj }\: of \: the \: required \: angle \: = 15. \\ now \: lets \: apply \: \boxed{TOA}\to \: \tan( \theta) = \frac{opp}{adj} \to\\ \tan( \theta) = \frac{opp}{adj} = \frac{35}{15} = 2.3333333333 \\ \theta = \tan {}^{ - 1} (2.3333333333) \\ \boxed{\theta = 66.80}[/tex]
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