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A 12 volt battery is connected to two resistors in series. The first resistor has a resitance value of 5 Ohms and the current through the circuit is 1.5 Amps. What is the value of the second resistor?

a
9 Ohms
b
1.5 Ohms
c
5 Ohms
d
3 Ohms

Respuesta :

Oceans

Answer:

D) 3 ohms

Explanation:

According to one law

V = IR

Where V = voltage or potential difference

I =current

R =resistance

Making R the subject

R= V/I

R= 12/1.5

R=8 ohms

Sum of resistance of resistors in series equals the total resistance

R(total) = R1+ R2

8 =5+ R2

8-5=R2

3=R2

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