On a coordinate plane, a solid straight line has a negative slope and goes through (0, 3) and (1, negative 1). Everything to the right of the line is shaded.
How to draw regions covered by inequalities?
Suppose there is inequality given as: y ≥ f(x)
The region it covers is the region of value pairs (x,y) for which this inequality holds true.
We've to draw the region covered by it.
For a function y = f(x), there is y > f(x) on one side of the graph of the function y = f(x) in XY plane, and on other side there is y < f(x).
A manufacturing machine has two processes. One of them is repeated 4 times and the second only once. The entire cycle can take no longer than 3 minutes.
Let t be the time of the first process in minutes
s be the time of the second process in minutes
we know that the time of the first process multiplied by 4 (because is repeated 4 times) plus the time of the second process multiplied by 1 (because is repeated only once) must be less than or equal to 3 minutes
So, The inequality that represents this situation is
[tex]4t + s\leq 3[/tex]
The y-intercept of the solid line is the point (0,3)
The x-intercept of the solid line is the point (0.75,0)
The slope of the solid line is negative m=-4
On a coordinate plane, a solid straight line has a negative slope and goes through (0, 3) and (1, negative 1). Everything to the right of the line is shaded.
Learn more about graphing inequalities here:
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