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A crane lifts a 425 kg steel beam vertically upward a distance of 614.4 m
How much work does the crane do on the beam if the beam accelerates upward at 1.8 m/s2? Neglect frictional forces.

Respuesta :

PHYSICS

*not sure about the answer but here we go*

Mass = 425 kg

distance = 614.4 m

acceleration = 1.8 m/s²

Answer :

Count Force first.

[tex]f \: = m \: \times a[/tex]

F = 425 × 1,8

F = 765 N ✅

Now let's count Work.

[tex]w \: = \: f \: \times s[/tex]

W = 765 × 614.4

W = 470016 J ✅

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