Given:
Triangle ABC is dilated by a scale factor of [tex]\dfrac{3}{8}[/tex] to create triangle A'B'C'.
To find:
The area of triangle ABC is u square units.
Solution:
Triangle ABC is dilated to create triangle A'B'C'. It means both triangles are similar.
We know that, the ratio of the areas of similar triangles is the square of the scale factor.
[tex]\dfrac{ar(\Delta A'B'C')}{ar(\Delta ABC)}=\left(\dfrac{3}{8}\right)^2[/tex]
The area of triangle ABC is u square units.
[tex]\dfrac{ar(\Delta A'B'C')}{u}=\dfrac{9}{64}[/tex]
Multiply both sides by u.
[tex]ar(\Delta A'B'C')=\dfrac{9}{64}u[/tex]
Therefore, the area of triangle A'B'C' is [tex]\dfrac{9}{64}u[/tex] sq. units.