Answer:
[tex]M=7.3x10^{-9}\frac{mol}{L}[/tex]
Explanation:
Hello!
In this case, since the values are not given in the question you asked, we are going to use a dataset found on ethernet for this problem, however, if you were given with different values you can follow the exact procedure with those you have.
In such a way, we consider 0.0011 μmol of silver oxide in a 150-mL volumetric flask until the mark, which means that the volume of the solution is 150 mL, in such way, since the molarity is defined by:
[tex]M=\frac{n_{solute}}{V_{solution}}[/tex]
In units of mol/L we need to convert from μmol to mol as shown below:
[tex]n=0.0011\mu mol*\frac{1mol}{1x10^6\mu mol} =1.1x10^{-9}mol[/tex]
Next the volume in liters is:
[tex]V=150 mL*\frac{1L}{1000mL} =0.150L[/tex]
Thus, the concentration in mol/L turns out:
[tex]M=\frac{1.1x10^{-9}mol}{0.150L}\\\\M=7.3x10^{-9}\frac{mol}{L}[/tex]
Best regards!
