Answer:
a) [GaCl4]^- Tetrahedral
[SbCl4]^- See saw
b) [SbCl2]^+ [GaCl4]^-
Explanation:
If we look at the anion, [GaCl4]^-, we can see that it contains four electron domains and no lone pairs so we usually expect it to be in a terahedral geometry.
Looking at [SbCl4]^-, there are five electron domains with one lone pair. It is usually expected to exhibit a seesaw molecular geometry.
[SbCl2]^+ (18 valence electrons) is known to possess a bent geometry(due to the presence of a lone pair of electrons on the central atom, Sb) while [GaCl2]^+ (16 valence electrons) is known to possess a linear geometry.
Since it was stated in the question that the cation must posses a bent geometry, then the correct structure is; [SbCl2]^+ [GaCl4]^-