⚠️PLEASE HELP ASAP THANKS ⚠️
Solve the following system of equations algebraically.
2x + y + 3z = 3
-3x + 3y - 2z=-8
5x – y + 5z = 13

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Answer:

Let's solve for x.

−3x+3y−2z=−8

Step 1: Add -3y to both sides.

−3x+3y−2z+−3y=−8+−3y

−3x−2z=−3y−8

Step 2: Add 2z to both sides.

−3x−2z+2z=−3y−8+2z

−3x=−3y+2z−8

Step 3: Divide both sides by -3.

−3x−3=−3y+2z−8−3

x=y+−23z+83

Answer:

x=y+−23z+83

Let's solve for x.

5x−y+5z=13

Step 1: Add y to both sides.

5x−y+5z+y=13+y

5x+5z=y+13

Step 2: Add -5z to both sides.

5x+5z+−5z=y+13+−5z

5x=y−5z+13

Step 3: Divide both sides by 5.

5x5=y−5z+135

x=15y−z+135

Answer:

x=15y−z+135

Let's solve for x.

2x+y+3z=3

Step 1: Add -y to both sides.

2x+y+3z+−y=3+−y

2x+3z=−y+3

Step 2: Add -3z to both sides.

2x+3z+−3z=−y+3+−3z

2x=−y−3z+3

Step 3: Divide both sides by 2.

2x2=−y−3z+32

x=−12y+−32z+32

Answer:

x=−12y+−32z+32

Step-by-step explanation:

I'm not sure what variable to solve for so j just chose x