The square root of a number is 1/2th power of the number. Two integer which are between the [tex]\sqrt{55}[/tex] and [tex]\sqrt{88}[/tex] are 8 and 9..
To find the integers, we need to calculate the square roots of all the options.
What is square root?
Square root of number is the number which is when multiplied by itself gives the original number.
The square root of a number is 1/2th power of the number. Such as,
[tex]\sqrt{a} =a^{1/2}[/tex]
Given information-
The integer from the given options has to choose which are between the square root numbers [tex]\sqrt{55}[/tex] and [tex]\sqrt{88}[/tex].
Find out the square root of all the numbers to compare with given numbers.
- The square root of the number 6 is,
[tex]6=\sqrt{6\times6} \\6=\sqrt{36}[/tex]
- The square root of the number 7 is,
[tex]7=\sqrt{7\times7} \\7=\sqrt{49}[/tex]
- The square root of the number 8 is,
[tex]8=\sqrt{8\times8} \\8=\sqrt{64}[/tex]
- The square root of the number 9 is,
[tex]9=\sqrt{9\times9} \\9=\sqrt{81}[/tex]
- The square root of the number 10 is,
[tex]10=\sqrt{10\times10} \\10=\sqrt{100}[/tex]
As the square root [tex]\sqrt{64}[/tex] and [tex]\sqrt{81}[/tex] is between the square root numbers [tex]\sqrt{55}[/tex] and [tex]\sqrt{88}[/tex].
Hence two integer which are between the [tex]\sqrt{55}[/tex] and [tex]\sqrt{88}[/tex] are 8 and 9..
Learn more about the square root of a number here;
https://brainly.com/question/15329983
