Respuesta :

jjrudolf8

Answer:

(y-2)^2/9-x^2/25=1

adioabiola

The standard form of the equation -9x^2+25y^2-100y-125=0 in standard form is; (y -2)²/3² - x²/5² = 1.

What is the standard form of the equation?

According to the task content;

  • The equation given is; -9x^2+25y^2-100y-125=0.

By dividing the equation through by 225, the resulting equation is;

  • y²/9 - 4y/9 - x² -5/9 = 0

  • 1/9 (y-2)² - 4/9 - x²/25 -5/9 = 0.

  • 1/9 (y-2)² - x²/25 = 1.

Hence, the standard form of the equation is;

  • (y -2)²/3² - x²/5² = 1.

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